1/4x^3-3/4x^2+1

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Solution for 1/4x^3-3/4x^2+1 equation: 


x in (-oo:+oo)

(1/4)*x^3-((3/4)*x^2)+1 = 0

(1/4)*x^3+(-3/4)*x^2+1 = 0

(1/4)*x^3+(-3/4)*x^2+1 = 0

(1/4)*x^3+(-3/4)*x^2+1 = 0 // * 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

x^3-3*x^2+4 = 2

1

-1

x = -1

x^3-3*x^2+4 = 0

-1

x+1

x^2-4*x+4

x^3-3*x^2+4

x+1

-x^3-x^2

4-4*x^2

4*x^2+4*x

4*x+4

-4*x-4

0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

x in { 2, 2, -1} 

x in { 2, 2, -1 }

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